Day 6 -- Mesh Analysis Continued (week 3)

In this lab, we continued mesh analysis with the use of two power supplies and various resistors. Our goal was to find the voltage through two circuit elements by first calculating the current flowing through them. We achieved this by method of mesh currents and used our values for i1, i2, and i3, in order to calculate the voltage through the 22 kΩ and 1.8 kΩ resistors. With our predictions, we tested our circuit and proved the accuracy of this method. 

Mesh current values: 

i1 =  0.898 mA

i2 =  -0.112 mA

i3 =  0.260 mA

V1 = (0.112 mA)*(22 kΩ)

      = 2.47 V

Setup of circuit respective to schematic

Measured value of voltage through 22 kΩ resistor

[Insert image of measured voltage through 1.8 kΩ]

Measured voltage through 22 kΩ; V1 = 2.45 V ± 0.005 V

Measured voltage through 1.8kΩ; V2 = [insert]

Expected V1 = 2.47 V

Expected V2 = 0.468 V

Percent differences

[insert]